1796 Pennsylvania gubernatorial election

1796 Pennsylvania gubernatorial election
← 1793 October 11, 1796 1799 →
	County Results ; Mifflin: 70–80% 80–90% 90–100%
Governor before election; Thomas Mifflin; Democratic-Republican	Elected Governor ; Thomas Mifflin; Democratic-Republican

The 1796 Pennsylvania gubernatorial election occurred on October 11, 1796. Incumbent Democratic-Republican governor Thomas Mifflin successfully sought re-election to a third term. For the second consecutive election, he was victorious over U.S. Representative Frederick Muhlenberg, the Federalist candidate, by a wide margin.

Results

Pennsylvania gubernatorial election, 1796^[2]^[3]
Party		Candidate	Votes	%
	Democratic-Republican	Thomas Mifflin (incumbent)	30,020	96.31
	Federalist	Frederick Muhlenberg	1,011	3.24
	Federalist	Anthony Wayne	139	0.45
Total votes			31,170	100.00

References

↑ "Public Notice is Hereby Given". Gazette of the United States, and Philadelphia daily advertiser. Philadelphia, Pa. October 8, 1796. p. 1. Retrieved December 12, 2022.
↑ "PA Governor General Election". OurCampaigns. Retrieved July 3, 2012.
↑ "Pennsylvania Gubernatorial Election Returns 1796". House of Representatives of the Commonwealth of Pennsylvania. Retrieved July 3, 2012.

[1] "Public Notice is Hereby Given". Gazette of the United States, and Philadelphia daily advertiser. Philadelphia, Pa. October 8, 1796. p. 1. Retrieved December 12, 2022.

[2] "PA Governor General Election". OurCampaigns. Retrieved July 3, 2012.

[results2-3] "Pennsylvania Gubernatorial Election Returns 1796". House of Representatives of the Commonwealth of Pennsylvania. Retrieved July 3, 2012.

[1]