1793 Pennsylvania gubernatorial election

1793 Pennsylvania gubernatorial election
← 1790 October 8, 1793 1796 →
	County Results; Mifflin: 50–60% 60–70% 70–80% 80–90% 90–100%; Muhlenberg: 50–60% 60–70%
Governor before election; Thomas Mifflin; Democratic-Republican	Elected Governor ; Thomas Mifflin; Democratic-Republican

The 1793 Pennsylvania gubernatorial election occurred on October 8, 1793. Incumbent Democratic-Republican governor Thomas Mifflin sought re-election to another term, defeating Federalist candidate and U.S. Representative Frederick Muhlenberg. Muhlenberg won only two counties: York and Bedford. However, Mifflin's 2–1 vote margin was down from his 10–1 victory margin in the 1790 gubernatorial election.^[2]

Results

Pennsylvania gubernatorial election, 1793^[3]^[4]
Party		Candidate	Votes	%
	Democratic-Republican	Thomas Mifflin (incumbent)	20,479	65.43
	Federalist	Frederick Muhlenberg	10,803	34.51
	Independent	Alexander McDowell	8	0.03
	N/A	Others	11	0.04
Total votes			31,301	100.00

References

↑ "Article II". Constitution of the Commonwealth of Pennsylvania - 1790 (PDF).
↑ Tinkcom, Harry Marlin. 1950. The Republicans and Federalists in Pennsylvania: 1790-1801. Harrisburg: Pennsylvania Historical and Museum Commission, p. 138
↑ "PA Governor General Election". OurCampaigns. Retrieved July 3, 2012.
↑ "Pennsylvania Gubernatorial Election Returns 1793". House of Representatives of the Commonwealth of Pennsylvania. Retrieved July 3, 2012.

[1] "Article II". Constitution of the Commonwealth of Pennsylvania - 1790 (PDF).

[2] Tinkcom, Harry Marlin. 1950. The Republicans and Federalists in Pennsylvania: 1790-1801. Harrisburg: Pennsylvania Historical and Museum Commission, p. 138

[3] "PA Governor General Election". OurCampaigns. Retrieved July 3, 2012.

[results2-4] "Pennsylvania Gubernatorial Election Returns 1793". House of Representatives of the Commonwealth of Pennsylvania. Retrieved July 3, 2012.

[2]