How to print find match as well as run an -exec

Question

I was wanting to run a find and then execute a script on each match; however, I was wanting to print the name of the matched file above the output from each exec. How can I produce the following output:

$ find . -name 'something' -exec sh script.sh {} \;
./something_1
output from 
script.sh something_1
./something_2
output from
script.sh something_2

I am currently only getting the output from script.sh. I tried -exec echo {} && sh script.sh {} \; with no success.

I would prefer a solution using -exec or xargs -print0, i.e., not prone to problems with white space.

Answer 1

find prints all matching files by default if you don't specify any other action.

When you do -exec ..., it replaces the -print.

When you put two actions next to each other, it means AND.

So just do both:

$ find . -name 'something' -print -exec sh script.sh {} \;

Answer 2

Try doing this :

$ find . -name 'something' -exec sh script.sh {} \; |
    script.sh |
    script.sh