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I have some batch tests which dump data files of the following format in a folder. Each test dumps 1 file and the file name is a generic serial number. I would like to generate a list of all failed log filenames with the Testname.

I can use xargs but unable to print out the Testname. Following script dumps every log file, and it's workable though I would like a better solution.

grep 'Fail\|Testname' *.log

Sample File test_0123.log

[other log of 20MB]
* Result : Pass/Fail
* Testname : test_example_rsa_key_gen
[other log  and trailer]
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  • Is the log filename the value of the field Testname? And what is the Testcase in grep 'Fail\|Testcase' *.log? Commented Jan 23, 2019 at 5:20
  • Is the content of each log file just the two lines with Result and Testname, or are there more lines? Commented Jan 23, 2019 at 5:29
  • That's a typo. Each file contains only one testname and one verdict, but thousands of lines before and after those two lines. This line works now. Thank you. grep -A1 'Fail' *.log | grep 'Testcase'. Commented Jan 23, 2019 at 6:52

1 Answer 1

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perl -0777ne 'if ( /Result : Fail/ and /Testname : (\S+)/ ) { print "filename: $ARGV; testname: $1" }'  *.log
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  • Thank you! I got a Out of memory error with Perl. The log files is double digit MB each. A shell script like grep would be more efficient. Commented Jan 23, 2019 at 4:26
  • You don't have double digit MB of memory available? Use this: grep -A1 "^..Result : Fail" *.log | grep :..Testname.: Commented Jan 23, 2019 at 5:18
  • Yes I do. But there are thousands of log files. I managed to get it done with this: grep -A1 'Fail' *.log | grep 'Testcase' Commented Jan 23, 2019 at 6:50

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