Bash script: parse subdirectory and not current directories

Question

I'm trying to parse subdirectory names, but the output breaks the names up into individual words.

Eg. If the subdirectory name is "Hello World", the output will be:

.  
Hello  
World  

The following code works, but the output includes the current directory, which I don't want:

find "$my_dir" -maxdepth 1 -type d -print0 |
    while IFS= read -rd '' dir;
        do 
            echo "$dir"; 
        done

I'm trying to include an if statement that eliminates the current directory from the output, but it seems the code still sees individual words for each subdirectory name:

find "$my_dir" -maxdepth 1 -type d -print0 |  
    while IFS= read -rd '' dir;
        do 
            if ["$dir" != "."]; then
                echo "$dir"
            fi
        done

Answer 1

The breaking on spaces occurs in your read command, but you don't need this anyway. Also, your if logic is flawed. It would work only if my_dir equals to ., otherwise find would not generate a . in its output. Finally, you state in your example, that you want only the names of the directories, not the whole path, but in the way you wrote it, find would pass the path to stdout.

Here is an easier solution:

find "$my_dir" -maxdepth 1 -type d -exec basename {} \;|tail -n +2

The trick here is the tail command. You want to exclude the starting directory ($my_dir) from the output. find always outputs this directory first (unless you explicitly require depth-first traversal), so you simply have to drop the first line from the resulting output.

Answer 2

If you have it, use the -mindepth option, which can be used here to exclude the topmost directory in your tree

find "$my_dir" -mindepth 1 -maxdepth 1 -type d -print0

However, since you also have -maxdepth limiting the depth, why not just use a for loop

for dir in "$my_dir"/*
do
    [[ -d "$dir" ]] || continue    # only directories
    echo "${dir/*\/}"              # just basename
done