How to get list of files with not having search string [duplicate]

Question

I have a requirement to display all files in a directory which doesn't have CountOfFilesTransmitted=0 string in them.

If I give below command it gives only those files which has CountOfFilesTransmitted=1

find . -type f | xargs grep -l "CountOfFilesTransmitted=1"

Gives: 1.log, 2.log, 10.log

find . -type f | xargs grep -l "CountOfFilesTransmitted=1" -- gives 3.log, 7.log

There are logs in that directory with 0 to 100 files Transmitted I have to give 101 entries. Is there a way to get filenames which have non zero?

something like "find . -type f | xargs grep -l "CountOfFilesTransmitted!=0" which should return all files which doesn't have "CountOfFilesTransmitted=0" string.

Answer 1

This Answer will only work IF a file does not also contain the pattern of CountOfFilesTransmitted=0 assuming that the goal OP has is to show to files that contain that pattern at all.

find . -type f | xargs grep -le "CountOfFilesTransmitted=[1-9]"

using -e to allow for regex