Hashing a tuple not matching the expected value in python

Question

I am trying to solve the below problem:

Given an integer, n , and n space-separated integers as input, create a tuple, t , of those n integers. Then compute and print the result of hash(t).

I am using python 3. My code is

if __name__ == '__main__':
    n = int(input())
    integer_list = map(int, input().split())
    t = tuple(integer_list)
    print(hash(t))

The expected output is 3713081631934410656 but I am getting -3550055125485641917. I think my code is correct. Why am i getting a different output?

If I am using Pypy3, I am getting the correct output 3713081631934410656 but not with Python 3

Answer 1

Python doesn't promise that tuple hashing will produce any particular output. There is no such thing as the "correct" output for hash(some_tuple). The tuple hash implementation is free to change, and it has changed in Python 3.8.

Your assignment was likely written for a different Python version than the one you're testing on, without consideration of the fact that the tuple hash algorithm is an implementation detail.

Answer 2

If you are solving a hacker rank tuple problem, use the coding language Pypy3, and the output will be correct. Use the below code

if __name__ == '__main__':
    n = int(input())
    integer_list = map(int, input().split())
    print(hash(tuple(integer_list)))

Answer 3

I had the same problem, so it was necessary to first make the list and then convert it to a tuple only at the time of printing.

if __name__ == '__main__':
    n = int(input())
    t = map(int, input().split())
    print(hash(tuple(t)))