I've previously converted a byte array into a file conataining the binary equivalents of all the values in that byte array. Now how do do I convert those binary values back into a byte array??
Like for example...my byte array starts with values 7, 17, 118, 7.... And my text file conatining the binary values shows 00000111000100010111011000000111....
Read the file 8 characters at a time and use Integer.parseInt(chars, 2) where chars is the 8 characters you read in as a String. Repeat until the file is completely read.
char[] buff = new char[8]; while (rdr.ready()) {int n = rdr.read(buff, 0, 8); /* test that n==8, then process buff */} (If the file contains only the characters '0' and '1', it doesn't actually make a difference, because those characters have one-byte encodings. But it's generally better practice to use a Reader instead of an InputStream when you want characters.)(byte) Integer.parseInt(buff, 2). The problem is that "10001010" (-118 as a byte in binary) is not interpreted by Byte.parseByte as a sign bit followed by seven value bits; it is interpreted as a signed number in base 2. So instead of -118, it reads it as +138, which does not fit in a byte. To get -118, it would have to see the string "-1110110".use the input stream
InputStream is = new FileInputStream(new File("filen.ame"));
is.read(byte[] b, 0, len(file))
