Convert array Byte To Binary

Question

please any one can help me to convert the ascciiText to binary such as 49 have binary 00110001 and 48 is 00110010 and so on this is my code

import java.lang.String;
import java.util.Scanner;
import java.lang.*;
import java.io.*;
import java.util.*;

public class encrption {

public static void main(String[] args){

     // INPUT: KeyText   (StrKey).
    // OUTPUT: Ciphertext (ConcatenatedData).
   //String ConcatenatedData; 


    // Read data from user.
    Scanner in = new Scanner(System.in);
    System.out.println("Enter Your PlainText");
    String StrValue = in.nextLine();
    System.out.println("Enter Your KeyText ");
    String StrKey = in.nextLine();

  // Print the Concatenated Data.

 String ConcatenatedData = StrKey.concat(StrValue);
       System.out.println("the Concatenated Data is :"+ConcatenatedData);

  // Convering the Concatenated data to Ascii data.

 try { 
  byte[] asciiText = ConcatenatedData.getBytes("US-ASCII");


    System.out.println(Arrays.toString(asciiText)); 

}

 catch (java.io.UnsupportedEncodingException e)
     { e.printStackTrace(); }

Please any one can help me to convert the series of ascciiText to binary such as 49 have binary 00110001 and 48 is 00110010 and so on

Configuration: encrption - JDK version 1.8.0_40

Enter Your PlainText welcome Enter Your KeyText 123 the Concatenated Data is :123welcome [49, 50, 51, 119, 101, 108, 99, 111, 109, 101]

Process completed.

Integer.toBinaryString()?

fge
– fge

2015-09-17 10:26:35 +00:00
Commented Sep 17, 2015 at 10:26 — fge
– fge, Commented Sep 17, 2015 at 10:26

Peter Lawrey · Accepted Answer · 2015-09-17 11:29:49Z

1

Simialr on @Paul's solution but written another way.

String toBinary(byte b) {
    StringBuilder sb = new StringBuilder(8);

    for(int i = 7 ; i >= 0 ; i--)
        sb.append((char) ('0' + ((b >> i) & 1));

    return sb.toString();
}

answered Sep 17, 2015 at 11:29

Peter Lawrey

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Comments

score 1 · Accepted Answer · 2015-09-18 12:07:16Z

1

Since byte doesn't provide any method for this you'll have to use Integer:

byte[] b = ...;//you're array
String binStr = "";

for(byte v : b)
    binStr += Integer.toBinaryString(v);

Or you could write your own method. Wouldn't be too difficult aswell:

String toBinary(byte b){
    char[] binArr = new char[8];

    //if a bit is 1, emplace '1' at the respective position in the array, else 0
    for(int i = 0 ; i < 8 ; i++)
        binArr[7 - i] = (b & (1 << i)) == 0 ? '0' : '1';

    return new String(binArr);
}

edited Sep 18, 2015 at 12:07

answered Sep 17, 2015 at 10:29

user4668606

3 Comments

عابده لله Over a year ago

when adding this line[String binStr = Integer.toBinaryString(ascciiText)] gives to me this error error: incompatible types: byte[] cannot be converted to int

user4668606 Over a year ago

the reason for this is pretty simple: Integer.toBinaryString() expects a numeric type as parameter, not an Array, as shown in the example. You'll have to iterate over the array and transform every single byte on its own

عابده لله Over a year ago

can you do it for me

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