Python: Finding Average of Numbers

Question

My task is to: "Write a program that will keep asking the user for some numbers. If the user hits enter/return without typing anything, the program stops and prints the average of all the numbers that were given. The average should be given to 2 decimal places. If at any point a 0 is entered, that should not be included in the calculation of the average"

I've been trying for a while, but I can't figure out how to make the programs act on anything I instruct when the user hits 'enter' or for it to ignore the 0. This is my current code:

count = 0
sum = 0
number = 1
while number >= 0:
    number = int(input())
    if number == '\n':
        print ('hey')
        break
    if number > 0:
        sum = sum + number
        count= count + 1
    elif number == 0:
        count= count + 1
    number += 1
avg = str((sum/count))
print('Average is {:.2f}'.format(avg))

I've been trying for a while, but I can't figure out how to make the programs act on anything I instruct when the user hits 'enter' or for it to ignore the 0. Can you be more specific about which part you're struggling with? Have you tried breaking down the problem on paper, writing pseudocode, etc. ? — AMC
– AMC, Commented Jun 5, 2020 at 2:55

Thomas · Accepted Answer · 2020-06-14 21:55:36Z

1

You're very close! Almost all of it is perfect!

Here is some more pythonic code, that works. I've put comments explaining changes:

count = 0
sum = 0
# no longer need to say number = 1
while True:  # no need to check for input number >= 0 here
    number = input()
    if number = '':  # user just hit enter key, input left blank
        print('hey')
        break
    if number != 0:
        sum += int(number)  # same as sum = sum + number
        count += 1  # same as count = count + 1
    # if number is 0, we don't do anything!
print(f'Average is {count/sum:.2f}')  # same as '... {:.2f} ...'.format(count/sum)

Why your code didn't work:

When a user just presses enter instead of typing a number, the input() function doesn't return '\n', rather it returns ''.

I really hope this helps you learn!

edited Jun 14, 2020 at 21:55

answered Jun 5, 2020 at 2:47

Thomas

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2 Comments

Elle Over a year ago

Thank you, this really helped! I spent hours and gave my headache over something so small lol. (Thank you for taking the time to add comments and letting me know why what I did didn't work)

Thomas Over a year ago

Awesome! I’m so glad this helped. It would mean a lot to me if you marked this as correct and gave an upvote :)

Red · Accepted Answer · 2020-06-05 04:10:45Z

Try this:

amount = 0 # Number of non-zero numbers input
nums = 0 # Sum of numbers input
while True:
    number = input()
    if not number: # Breaks out if nothing is entered
        break
    if int(number) != 0: # Only add to the variables if the number input is not 0
        nums+=int(number)
        amount += 1

print(round(nums/amount,2)) # Print out the average rounded to 2 digits

Input:

Output:

2.5

Or you can use numpy:

import numpy as np
n = []
while True:
    number = input()
    if not number: # Breaks out if nothing is entered
        break
    if int(number) != 0: # Only add to the variables if the number input is not 0
        n.append(int(number))

print(round(np.average(n),2)) # Print out the average rounded to 2 digits

Use of mean() is the same, average() has an added advantage of a weighting option. You are also appending strings - convert: n.append(str(number))

leopardxpreload · Accepted Answer · 2020-06-05 04:01:41Z

0

A list can store information of the values, number of values and the order of the values. Try this:

numbers = []
while True:
    num = input('Enter number:')
    if num == '':
        print('Average is', round(sum(numbers)/len(numbers), 2))   # print
        numbers = []   # reset
    if num != '0' and num != '': numbers.append(int(num))  # add to list

Benefit of this code, it does not break out and runs continuously.

edited Jun 5, 2020 at 4:01

answered Jun 5, 2020 at 2:50

leopardxpreload

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Python: Finding Average of Numbers

3 Answers 3

Why your code didn't work:

2 Comments

1 Comment

Benefit of this code, it does not break out and runs continuously.

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3 Answers 3

Why your code didn't work:

2 Comments

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Benefit of this code, it does not break out and runs continuously.

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