can anyone help?
import math
a = int(raw_input('Enter Average:')) # Average number probability
c = int(raw_input('Enter first number:')) #
d = int(raw_input('Enter last number:')) #
e = 2.71828
for b in range(c,d+1):
x = (a**b)/math.factorial(b)*(e**-a)
odd = round (1/x*0.92, 2)
print odd
How to find average value of odd?
You can do two things:
odd values into, e.g., a list, then average the result.(I'm assuming that by "average" you mean "arithmetic mean". If you mean something different, the details are different, but the basic idea is the same.)
For the first:
odds = []
for b in range(c,d+1):
x = (a**b)/math.factorial(b)*(e**-a)
odd = round (1/x*0.92, 2)
print odd
odds.append(odd)
print sum(odds) / len(odds)
If you don't what sum or len do, read the docs.
For the second:
total, count = 0, 0
for b in range(c,d+1):
x = (a**b)/math.factorial(b)*(e**-a)
odd = round (1/x*0.92, 2)
print odd
total += odd
count += 1
print total / count
a=int(raw_input("probability: ")); result=sum([round(1/((a**b)/math.factorial(b)*(2.71828**(-a)))*0.92, 2) for count,b in enumerate(range(int(raw_input("start: ")), int(raw_input("end: "))+1),1)])/countcount variable outside of the list comp)
count… but you don't need it thanks to statistics. Which means you don't need enumerate either. Plus input is shorter than raw_input, so I can waste even more of my comment writing text and still fit the 3.4 code with plenty of room to spare: a=int(input('probability:')); result=statistics.mean(round(1/((a**b)/math.factorial(b)*(2.71828**-a))*0.92, 2) for b in range(int(input('start:')),int(input('end:'))+1)). That's 169 characters vs. 202, proving that 3.x is 19.5% better than 2.x. :)statistics!)