How to delete from a text file, all lines that contain a specific string?

Question

How would I use sed to delete all lines in a text file that contain a specific string?

Answer 1

To remove the line and print the output to standard out:

sed '/pattern to match/d' ./infile

To directly modify the file – does not work with BSD sed:

sed -i '/pattern to match/d' ./infile

Same, but for BSD sed (Mac OS X and FreeBSD) – does not work with GNU sed:

sed -i '' '/pattern to match/d' ./infile

To directly modify the file (and create a backup) – works with BSD and GNU sed:

sed -i.bak '/pattern to match/d' ./infile

Answer 2

There are many other ways to delete lines with specific string besides sed:

AWK

awk '!/pattern/' file > temp && mv temp file

Ruby (1.9+)

ruby -i.bak -ne 'print if not /test/' file

Perl

perl -ni.bak -e "print unless /pattern/" file

Shell (bash 3.2 and later)

while read -r line
do
  [[ ! $line =~ pattern ]] && echo "$line"
done <file > o
mv o file

GNU grep

grep -v "pattern" file > temp && mv temp file

And of course sed (printing the inverse is faster than actual deletion):

sed -n '/pattern/!p' file

Answer 3

You can use sed to replace lines in place in a file. However, it seems to be much slower than using grep for the inverse into a second file and then moving the second file over the original.

e.g.

sed -i '/pattern/d' filename      

or

grep -v "pattern" filename > filename2; mv filename2 filename

The first command takes 3 times longer on my machine anyway.

Answer 4

The easy way to do it, with GNU sed:

sed --in-place '/some string here/d' yourfile

Answer 5

You may consider using ex (which is a standard Unix command-based editor):

ex +g/match/d -cwq file

where:

• + executes given Ex command (man ex), same as -c which executes wq (write and quit)
• g/match/d - Ex command to delete lines with given match, see: Power of g

The above example is a POSIX-compliant method for in-place editing a file as per this post at Unix.SE and POSIX specifications for ex.

---

The difference with sed is that:

sed is a Stream EDitor, not a file editor.^BashFAQ

Unless you enjoy unportable code, I/O overhead and some other bad side effects. So basically some parameters (such as in-place/-i) are non-standard FreeBSD extensions and may not be available on other operating systems.

Answer 6

I was struggling with this on Mac. Plus, I needed to do it using variable replacement.

So I used:

sed -i '' "/$pattern/d" $file

where $file is the file where deletion is needed and $pattern is the pattern to be matched for deletion.

I picked the '' from this comment.

The thing to note here is use of double quotes in "/$pattern/d". Variable won't work when we use single quotes.

Answer 7

You can also use this:

 grep -v 'pattern' filename

Here -v will print only other than your pattern (that means invert match).

Answer 8

To get a inplace like result with grep you can do this:

echo "$(grep -v "pattern" filename)" >filename

Answer 9

Delete lines from all files that match the match

grep -rl 'text_to_search' . | xargs sed -i '/text_to_search/d'

Answer 10

I have made a small benchmark with a file which contains approximately 345 000 lines. The way with grep seems to be around 15 times faster than the sed method in this case.

I have tried both with and without the setting LC_ALL=C, it does not seem change the timings significantly. The search string (CDGA_00004.pdbqt.gz.tar) is somewhere in the middle of the file.

Here are the commands and the timings:

time sed -i "/CDGA_00004.pdbqt.gz.tar/d" /tmp/input.txt

real    0m0.711s
user    0m0.179s
sys     0m0.530s

time perl -ni -e 'print unless /CDGA_00004.pdbqt.gz.tar/' /tmp/input.txt

real    0m0.105s
user    0m0.088s
sys     0m0.016s

time (grep -v CDGA_00004.pdbqt.gz.tar /tmp/input.txt > /tmp/input.tmp; mv /tmp/input.tmp /tmp/input.txt )

real    0m0.046s
user    0m0.014s
sys     0m0.019s

Answer 11

SED:

• '/James\|John/d'
• -n '/James\|John/!p'

AWK:

• '!/James|John/'
• /James|John/ {next;} {print}

GREP:

• -v 'James\|John'

Answer 12

You can also delete a range of lines in a file. For example to delete stored procedures in a SQL file.

sed '/CREATE PROCEDURE.*/,/END ;/d' sqllines.sql

This will remove all lines between CREATE PROCEDURE and END ;.

I have cleaned up many sql files withe this sed command.

Answer 13

perl -i    -nle'/regexp/||print' file1 file2 file3
perl -i.bk -nle'/regexp/||print' file1 file2 file3

The first command edits the file(s) inplace (-i).

The second command does the same thing but keeps a copy or backup of the original file(s) by adding .bk to the file names (.bk can be changed to anything).

Answer 14

to show the treated text in console

cat filename | sed '/text to remove/d' 

to save treated text into a file

cat filename | sed '/text to remove/d' > newfile

to append treated text info an existing file

cat filename | sed '/text to remove/d' >> newfile

to treat already treated text, in this case remove more lines of what has been removed

cat filename | sed '/text to remove/d' | sed '/remove this too/d' | more

the | more will show text in chunks of one page at a time.

Answer 15

I found most of the answers not useful for me, If you use vim I found this very easy and straightforward:

:g/<pattern>/d

Source

Answer 16

echo -e "/thing_to_delete\ndd\033:x\n" | vim file_to_edit.txt

Answer 17

Curiously enough, the accepted answer does not actually answer the question directly. The question asks about using sed to replace a string, but the answer seems to presuppose knowledge of how to convert an arbitrary string into a regex.

Many programming language libraries have a function to perform such a transformation, e.g.

python: re.escape(STRING)
ruby: Regexp.escape(STRING)
java:  Pattern.quote(STRING)

But how to do it on the command line?

Since this is a sed-oriented question, one approach would be to use sed itself:

sed 's/\([\[/({.*+^$?]\)/\\\1/g'

So given an arbitrary string $STRING we could write something like:

re=$(sed 's/\([\[({.*+^$?]\)/\\\1/g' <<< "$STRING")
sed "/$re/d" FILE

or as a one-liner:

 sed "/$(sed 's/\([\[/({.*+^$?]\)/\\\1/g' <<< "$STRING")/d" 

with variations as described elsewhere on this page.

Answer 18

cat filename | grep -v "pattern" > filename.1
mv filename.1 filename

Answer 19

Just in case someone wants to do it for exact matches of strings, you can use the -w flag in grep - w for whole. That is, for example if you want to delete the lines that have number 11, but keep the lines with number 111:

-bash-4.1$ head file
1
11
111

-bash-4.1$ grep -v "11" file
1

-bash-4.1$ grep -w -v "11" file
1
111

It also works with the -f flag if you want to exclude several exact patterns at once. If "blacklist" is a file with several patterns on each line that you want to delete from "file":

grep -w -v -f blacklist file

Answer 20

You can use good old ed to edit a file in a similar fashion to the answer that uses ex. The big difference in this case is that ed takes its commands via standard input, not as command line arguments like ex can. When using it in a script, the usual way to accomodate this is to use printf to pipe commands to it:

printf "%s\n" "g/pattern/d" w | ed -s filename

or with a heredoc:

ed -s filename <<EOF
g/pattern/d
w
EOF

Answer 21

This solution is for doing the same operation on multiple file.

for file in *.txt; do grep -v "Matching Text" $file > temp_file.txt; mv temp_file.txt $file; done

Answer 22

Here is a sd based solution:

sd "${pattern}\n?" "" <file>