Sed : replace string if a chaine is not included in it [duplicate]

Question

I have a variable "header", and if there is the chaine "last" inside it i'd like to do nothing, but if the chain "last" is not inside my variable, i'd like to delete the whole variable (header = "")

I was searching for sth like this, but obviously it doesn't work like this.

echo $header | sed "/!'last'//"

How to do a negation with sed? Can someone help me please?

Thank you

karakfa · Accepted Answer · 2016-03-21 12:42:08Z

0

or in awk

header=$(echo $header | awk '!/last/')

answered Mar 21, 2016 at 12:42

karakfa

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Ali ISSA · Accepted Answer · 2016-03-21 13:37:48Z

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header=`echo $header |  sed '/last/d'`

or

header=`echo $header |  sed -e 's/.*last.*//g'`

edited Mar 21, 2016 at 13:37

answered Mar 21, 2016 at 12:41

Ali ISSA

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