Remove everything before and after a string part in Android

Question

I want to get Amazon product ASIN from the URL here are some examples:

https://www.amazon.com/Premium-Flagship-Lenovo-Processor-Bluetooth/dp/B07H15QHT6/ref=sr_1_2_sspa?s=pc&ie=UTF8&qid=1537733386&sr=1-2-spons&keywords=laptop&psc=1


https://www.amazon.com/Youve-Got-Crabs-Creators-Exploding/dp/B07BKLT9B5/ref=mp_s_a_1_1?ie=UTF8&qid=1537733019&sr=8-1-spons&pi=AC_SX236_SY340_FMwebp_QL65&keywords=games&psc=1

I want to get that text after /dp/ and remove everything after that text like this

B07BKLT9B5 and B07H15QHT6

ʍѳђઽ૯ท · Accepted Answer · 2018-09-23 20:31:53Z

1

You can use:

split("dp")

And get 2 part or use substring() and indexOf() method.

edited Sep 23, 2018 at 20:31

ʍѳђઽ૯ท

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answered Sep 23, 2018 at 20:18

Chickenturtle

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Comments

Macmist · Accepted Answer · 2018-09-23 20:29:43Z

0

You can do something like that

public String getCode(String s) {
    int pos = s.indexOf("/dp/"); // find the position of the string "/dp/" in the url
    String substr = s.substring(pos + "/dp/".length()); // get everyting after dp
    String[] parts = substr.split("/"); // split at every '/' character
    return parts[0]; // your result will be the first element of the array
}

answered Sep 23, 2018 at 20:29

Macmist

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