I want to step the loop iterator explicitly inside the loop. Is there a 'nicer' way to do this than:
idx = iter(range(0, 10))
for i in idx:
print i
if i == 5:
print "consuming %i in step %i" % (next(idx), i)
Edit: I wander if there is a way to get access to the loop-iterator other than defining it explicitly as in my example.
Thanks!
data = list(range(10))
it = iter(data)
for i in it:
if i==5:
j = it.next()
print "Consuming {0},{1}".format(i,j)
else:
print i
results in
0
1
2
3
4
Consuming 5,6
7
8
9
You could define a generator to yield elements from the iterator singly or in pairs. This keeps the for-loop nice and simple, while isolating the filtering logic in the generator.
def my_filter(iterable):
result=[]
for i in iterable:
result.append(i)
if i==5:
continue
yield result
result=[]
idx = iter(range(0, 10))
for i in my_filter(idx):
print i
my_filter), so that it yields an object that contains either a single element from idx or multiple elements from idx. Ideally, the for-loop should process those objects homogenously -- it shouldn't care if the object contains a single element from idx or multiple elements.my_filter would generate my pairings; however my actual code is a bit more complicated - and the continue in the my_filter-loop would not work nicely. So it turns me back to the original question: how can I consume the next element within the same iteration... Maybe creating the iterator-object explicitly and using next() as in my initial example is the way to go for me... Thanks for you effort!
next(idx)? Isn't it explicit and nice enough?idxisn't already an iterator (eg. a list). It's also very uncommon practice to take thenextof an iterator while you're iterating over it. I'd strongly recommend against it.for i in range(0, 10)- but then I don't get access to the iterator-object...