Stop a python script from executing

Question

I have the below python script(server.py) in order to listen to a port and capture the requests from the client. I am calling this script from another python file(Main.py). My requirement is to stop executing server.py after certain amount of time. I tried using exit() at the last line of the file - server.py to stop the server and stop the execution of the file, however I was not able to stop the script from running and the server kept responding. Can anyone help me in letting me know where I am going wrong.

Server.py

bind_ip = "127.0.0.1"
bind_port = 2530

def servercreate():
    server = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
    server.bind((bind_ip,bind_port))
    server.listen(5)

    while True:
        client, addr = server.accept()
        print('[*] Accepted connection from: %s:%d' % (addr[0], addr[1]))
        client_handler = threading.Thread(target=handle_client, args=(client,))
        client_handler.start()


def handle_client(client_socket):
    request = client_socket.recv(2056)
    print('[*] Received: %s' % request)

    message = "{}"
    client_socket.send(message.encode('utf-8'))
    client_socket.close()

if __name__ == '__main__':
    servercreate()

Main.py

import Server
Server.servercreate()

Answer 1

if you don't want your code interrupted by time.sleep (which I think stops the code from running), use this:

import time
timeout = time.time() + 10

while True:
    print ('hello')
    if time.time() > timeout:
        print ('program terminated')
        break

if you want 10 minutes worth of time use:

timeout = time.time() + 60*10   

If you just want to stop the program running after a certain amount of time use something like

import time

x=0
while True:
    print ('waiting 5')
    time.sleep(5)
    x += 1
    if x == (10):
        break

the time.sleep is in seconds, break stops the loop and should end your program

update, try this:

import time


bind_ip = "127.0.0.1"
bind_port = 2530

def servercreate():

    #put minutes of time you want program to run for below
    minutes = 10
    timeout = time.time() + (60*minutes)

    server = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
    server.bind((bind_ip,bind_port))
    server.listen(5)

    while True:
        client, addr = server.accept()
        print('[*] Accepted connection from: %s:%d' % (addr[0], addr[1]))
        client_handler = threading.Thread(target=handle_client, args=(client,))
        client_handler.start()
        if time.time() > timeout:
            break


def handle_client(client_socket):
    request = client_socket.recv(2056)
    print('[*] Received: %s' % request)

    message = "{}"
    client_socket.send(message.encode('utf-8'))
    client_socket.close()


if __name__ == '__main__':
    servercreate()