Python comparing integers and using if

Question

Q = int(input("Enter a number."))
if Q > 30 and =< 40:
    import easygui
    easygui.msgbox("This number is greater than 30 and less than or equal to 40")

I don't know what's wrong it just says "Invalid Syntax" and highlights the equal sign in equal to or less than 40 before even running the code. easygui isn't the problem.

and =< 40 and what is smaller or equal to 40?

Dimitris Fasarakis Hilliard
– Dimitris Fasarakis Hilliard

2016-11-23 23:21:02 +00:00
Commented Nov 23, 2016 at 23:21 — Dimitris Fasarakis Hilliard
– Dimitris Fasarakis Hilliard, Commented Nov 23, 2016 at 23:21

Moinuddin Quadri · Accepted Answer · 2016-11-23 23:34:44Z

4

You probably meant to do this:

#             v mention `Q` here
if Q > 30 and Q <= 40:
#               ^ i.e. `<` before `=`

edited Nov 23, 2016 at 23:34

Moinuddin Quadri

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answered Nov 23, 2016 at 23:24

Carles Mitjans

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5 Comments

Carles Mitjans Over a year ago

Have you also changed =< to <=? The first option is not correct in python.

Deneb Over a year ago

If you changed both, the syntax is then correct normally.

juanpa.arrivillaga Over a year ago

And actually, Python allows the very nice construct 30 < Q <= 40

Anonymous Over a year ago

OK that worked, I guess I hadn't changed it back to <= since I was fiddling with it to try and fix it.

Chedi Bechikh Over a year ago

why if Q > 30 and Q < 40: it only work if i add = ?

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