if ( "compare string " and "compare int ")

Question

compared two strings inside the if statement and used " and " operator then compared two integers.

 if( issue == bk[i].name and bk[i].quan !=0 ):
            print " book is available"

I get this error

Traceback (most recent call last):
  File "C:\Users\DCC PCMC\Desktop\CSE\python projects\DSA project\lib_class.py", line 141, in                                      <module>
    if( issue == bk[i].name and bk[i].quan !=0 ):
AttributeError: 'int' object has no attribute 'name'

bk[i] is int your sequence b. I guess It should be some book object in your list b you have overwritten in your code before if statement: Add more code here. or your assignment is wrong. I think bk[i].name should be assigned in bk[i].quan — Grijesh Chauhan
– Grijesh Chauhan, Commented Aug 18, 2013 at 6:17
Can you edit your question to include an example of the structure of the bk list? — Bryan
– Bryan, Commented Aug 18, 2013 at 17:05

Ray Toal · Accepted Answer · 2013-08-18 06:17:20Z

1

The error message is pretty clear.

It is telling you you have an int with no attribute name.

Where do you use name? You use it here:

bk[i].name

So it must be the case that the value of bk[i] is an int. You probably expected it to be something else.

answered Aug 18, 2013 at 6:17

Ray Toal

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