How does int work in Java math equations?

Question

I've been reviewing my Java for a class I've taken for the whole year and haven't been doing well on. They have a separate review book called "Be Prepared." I want to see if I get the math behind this line.

result = (1 / 2) * n * (n + 1);    // result is 0.0

The thing is, this is basic basic basic. I need to know if I'm actually getting this. It looks like my like (1/2) is 0.5. That cast to an int is 0. That's why the whole thing is 0.0.

Am I right?

This book is how you get ready for the AP test. Anyone done eimacs who can help?

possible duplicate of Fahrenheit to Celsius conversion yields only 0.0 and -0.0 — devnull
– devnull, Commented Apr 13, 2014 at 3:47
it's an integer division, not floating point division then truncating down — phuclv
– phuclv, Commented Apr 13, 2014 at 3:53
If n is an int, then the result should be 0, not 0.0, unless result is of type double. — dansalmo
– dansalmo, Commented Apr 13, 2014 at 3:58

Community · Accepted Answer · 2017-05-23 12:05:37Z

7

(1 / 2) will return zero. both are integer and as per integer calculation it will return zero.

Try

result = (1.0 / 2) * n * (n + 1);

Please have a look at :

In Java the result of each operation is decided by the higher type involved in calculation. It doesn't matter in what type are you assigning the result.

for e.g

double d = 10/3;

the value of d will be 3.0 only not 3.33.

edited May 23, 2017 at 12:05

CommunityBot

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answered Apr 13, 2014 at 3:46

Braj

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1 Comment

pennstatephil Over a year ago

he's not actually looking to make this work, he just wants confirmation that his thinking is correct. it's a strange question.

matt · Accepted Answer · 2014-04-13 03:48:46Z

2

Yes, and note that 999 / 1000 will also return 0. It's truncation, not rounding down.

answered Apr 13, 2014 at 3:48

matt

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