int a = 1; int b = 10; int c = 3; int d = (1/10)*3 System.out.println(d) Result: 0
How do i make this Calculation work ? and round up or down ? It should be: (1/10)*3 = 0.1 * 3 = 0.3 = 0 and (4/10)*3 = 0.4 * 3 = 1.2 = 1
Thanks a lot!
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2OP, please accept your answer instead of adding a message to the question. Click the grey checkmark to the left of the answer. This signals to everyone that the question is indeed answered and you are satisfied with the answer.Marko Topolnik– Marko Topolnik2012-08-24 09:26:00 +00:00Commented Aug 24, 2012 at 9:26
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7 Answers
1 / 10
This is integer division and as integer division the result is 0. Then 0 * 3 = 0
You can use double literals:
1.0 / 10.0
2 Comments
Steve Kuo
Those are floats. To specify double append a
D.
Joachim Sauer
@SteveKuo: no, floating-point literals are
double by default. It's only a float if you suffix it with F (or f).Try:
int d = (int) (((double)4/10)*3);
Comments
1/10
This line return 0.so 0*3=0.Use double instead of int
answered Aug 24, 2012 at 8:14
Samir Mangroliya
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2 Comments
BigAl
And then cast it back, or round it to int, if you need to.
Petar Ivanov
This won't work - 1/10 is still integer division, so the result is 0 again (of type double)
as both a and b are integer so the output will also be int which makes 1/10 as 0 and then 0*3=0
Comments
You will want to perform the calculation using floating-point representation. Then you can cast the result back to an integer.
Comments
I note that you refer in your question to rounding up/down.
Math.round() will help you here.
Returns the closest long to the argument. The result is rounded to an integer by adding 1/2, taking the floor of the result, and casting the result to type long.
Comments
This will works
int a = 1;
int b = 10;
int c = 3;
int d = (1*3/10);
System.out.println(d);
