Java scanner input into array

Question

I'm wanting to put the input of a scanner into my array but I am getting the error:

Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 0

my code:

    public static void main(String[] args)
    {
        Scanner scanInput   =   new Scanner(System.in);
        Random randomGen    =   new Random();

        String captureString[]  = new String[] {};

        System.out.println("Please enter some words..");
        captureString[0]  =   scanInput.next();
        captureString[1]  =   scanInput.next();
        captureString[2]  =   scanInput.next();


        System.out.println("You entered: " + captureString[0] + " " + captureString[1] + " " + captureString[2]);

    }

}

I cannot use loops or conditionals (task) so is an array viable for this? or should I just use variables, only reason I want to use an array is because I want to do some string manipulation afterwards which can be a little awkward with variables

As I write this, you have three good explanations of why this happens. May I suggest you use an ArrayList<String> instead, as this will grow on demand. — Dawood ibn Kareem
– Dawood ibn Kareem, Commented Mar 15, 2014 at 4:22

Keerthivasan · Accepted Answer · 2014-03-15 04:20:54Z

3

Since you are getting three inputs, i'd suggest. Change it to String captureString[] = new String[3];. This is because, Arrays need to be initialized before they are used. Since you have initialiazed with no values. There will not be any index in it. So, when you access the index 0, you are getting ArrayIndexOutOfBoundsException. Hope it clarifies!

answered Mar 15, 2014 at 4:20

Keerthivasan

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Abimaran Kugathasan · Accepted Answer · 2014-03-15 04:20:41Z

2

Your array captureString has zero capacity. You can't add elements there. Java arrays can't grow, Use ArrayList, if the content intend to be grow

answered Mar 15, 2014 at 4:20

Abimaran Kugathasan

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