shell script on node.js

Question

I am very new to node.js, I am trying to create a node.js script with the execution of shell script in it.

Here is the code which i have .

var spawn = require('child_process').spawn
var _ = require('underscore');
var deploySh = spawn('sh', [ 'vij.sh' ], {
  cwd: process.env.HOME + '/u/qa/gv/node/scripts',
  env:_.extend(process.env, { PATH: process.env.PATH + ':/usr/local/bin' })
});

and when i try to execute it, i am facing the below issue. Can anyone help me on this?

node vijay

events.js:72
        throw er; // Unhandled 'error' event
              ^
Error: spawn ENOENT
    at errnoException (child_process.js:988:11)
    at Process.ChildProcess._handle.onexit (child_process.js:779:34)

You can drop sh and use spawn('vij.sh') - make sure that vij.sh has #!/bin/sh as the first line. — Jay
– Jay, Commented Feb 20, 2014 at 21:08
Hi, I have the #!/bin/sh at the first line. I modified the spawn but i get the same issue. — user3334590
– user3334590, Commented Feb 20, 2014 at 21:22
Hi Henk, yes i tried /bin/sh instead of sh, its the same error. — user3334590
– user3334590, Commented Feb 20, 2014 at 21:24

smertrios · Accepted Answer · 2014-02-21 00:49:13Z

1

spawn is complaining that it can't find 'sh', use 'bash' instead (you might also need to specify the full path to your script depending on your env setup.)

so I'd try:

spawn('bash', ['vij.sh'], ...
spawn('bash', ['/my/path/to/vij.sh'], ...
spawn('/my/path/to/vij.sh', [], ...

answered Feb 21, 2014 at 0:49

smertrios

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nhahtdh · Accepted Answer · 2015-03-19 02:46:51Z

0

var spawn = require('child_process').spawn
var _ = require('underscore');
var deploySh = spawn('sh', [ 'vij.sh' ], { 
  // cwd: process.env.HOME + '/u/qa/gv/node/scripts',
  env:_.extend(process.env, { PATH: process.env.PATH + ':/usr/local/bin' })
});

Comment cwd: line no. 4

Until now I don't know what is process.env.HOME value but this worked for me.

edited Mar 19, 2015 at 2:46

nhahtdh

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answered Mar 19, 2015 at 2:30

Sudhir Meena

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