How to sum array of numbers in Ruby?

Question

I have an array of integers.

For example:

array = [123,321,12389]

Is there any nice way to get the sum of them?

I know, that

sum = 0
array.each { |a| sum+=a }

would work.

Answer 1

For ruby >= 2.4 you can use sum:

array.sum

For ruby < 2.4 you can use inject:

array.inject(0, :+)

Note: the 0 base case is needed otherwise nil will be returned on empty arrays:

> [].inject(:+)
nil
> [].inject(0, :+)
0

Answer 2

Try this:

array.inject(0){ |sum, x| sum + x }

See Ruby's Enumerable Documentation

(note: the 0 base case is needed so that 0 will be returned on an empty array instead of nil)

Answer 3

array.reduce(0, :+)

While equivalent to array.inject(0, :+), the term reduce is entering a more common vernacular with the rise of MapReduce programming models.

inject, reduce, fold, accumulate, and compress are all synonymous as a class of folding functions. I find consistency across your code base most important, but since various communities tend to prefer one word over another, it’s nonetheless useful to know the alternatives.

To emphasize the map-reduce verbiage, here’s a version that is a little bit more forgiving on what ends up in that array.

array.map(&:to_i).reduce(0, :+)

Some additional relevant reading:

• http://ruby-doc.org/core-1.9.3/Enumerable.html#method-i-inject
• http://en.wikipedia.org/wiki/MapReduce
• http://en.wikipedia.org/wiki/Fold_(higher-order_function)

Answer 4

Alternatively (just for comparison), if you have Rails installed (actually just ActiveSupport):

require 'activesupport'
array.sum

Answer 5

For Ruby >=2.4.0 you can use sum from Enumerables.

[1, 2, 3, 4].sum

It is dangerous to mokeypatch base classes. If you like danger and using an older version of Ruby, you could add #sum to the Array class:

class Array
  def sum
    inject(0) { |sum, x| sum + x }
  end
end

Answer 6

New for Ruby 2.4.0

You can use the aptly named method Enumerable#sum. It has a lot of advantages over inject(:+) but there are some important notes to read at the end as well.

Examples

Ranges

(1..100).sum
#=> 5050

Arrays

[1, 2, 4, 9, 2, 3].sum
#=> 21

[1.9, 6.3, 20.3, 49.2].sum
#=> 77.7

Important note

This method is not equivalent to #inject(:+). For example

%w(a b c).inject(:+)
#=> "abc"
%w(a b c).sum
#=> TypeError: String can't be coerced into Integer

Also,

(1..1000000000).sum
#=> 500000000500000000 (execution time: less than 1s)
(1..1000000000).inject(:+)
#=> 500000000500000000 (execution time: upwards of a minute)

See this answer for more information on why sum is like this.

Answer 7

Ruby 2.4+ / Rails - array.sum i.e. [1, 2, 3].sum # => 6

Ruby pre 2.4 - array.inject(:+) or array.reduce(:+)

*Note: The #sum method is a new addition to 2.4 for enumerable so you will now be able to use array.sum in pure ruby, not just Rails.

Answer 8

Just for the sake of diversity, you can also do this if your array is not an array of numbers, but rather an array of objects that have properties that are numbers (e.g. amount):

array.inject(0){|sum,x| sum + x.amount}

Answer 9

ruby 1.8.7 way is the following:

array.inject(0, &:+) 

Answer 10

Ruby 2.4.0 is released, and it has an Enumerable#sum method. So you can do

array.sum

Examples from the docs:

{ 1 => 10, 2 => 20 }.sum {|k, v| k * v }  #=> 50
(1..10).sum                               #=> 55
(1..10).sum {|v| v * 2 }                  #=> 110

Answer 11

Also allows for [1,2].sum{|x| x * 2 } == 6:

# http://madeofcode.com/posts/74-ruby-core-extension-array-sum
class Array
  def sum(method = nil, &block)
    if block_given?
      raise ArgumentError, "You cannot pass a block and a method!" if method
      inject(0) { |sum, i| sum + yield(i) }
    elsif method
      inject(0) { |sum, i| sum + i.send(method) }
    else
      inject(0) { |sum, i| sum + i }
    end
  end
end

Answer 12

for array with nil values we can do compact and then inject the sum ex-

a = [1,2,3,4,5,12,23.45,nil,23,nil]
puts a.compact.inject(:+)

Answer 13

Method 1:

    [1] pry(main)> [1,2,3,4].sum
    => 10
    [2] pry(main)> [].sum
    => 0
    [3] pry(main)> [1,2,3,5,nil].sum
    TypeError: nil can't be coerced into Integer

Method 2:

   [24] pry(main)> [].inject(:+)
   => nil
   [25] pry(main)> [].inject(0, :+)
   => 0
   [4] pry(main)> [1,2,3,4,5].inject(0, :+)
   => 15
   [5] pry(main)> [1,2,3,4,nil].inject(0, :+)
   TypeError: nil can't be coerced into Integer
   from (pry):5:in `+'

Method 3:

   [6] pry(main)> [1,2,3].reduce(:+)
   => 6
   [9] pry(main)> [].reduce(:+)
   => nil
   [7] pry(main)> [1,2,nil].reduce(:+)
   TypeError: nil can't be coerced into Integer
   from (pry):7:in `+'

Method 4: When Array contains an nil and empty values, by default if you use any above functions reduce, sum, inject everything will through the

TypeError: nil can't be coerced into Integer

You can overcome this by,

   [16] pry(main)> sum = 0 
   => 0
   [17] pry(main)> [1,2,3,4,nil, ''].each{|a| sum+= a.to_i }
   => [1, 2, 3, 4, nil, ""]
   [18] pry(main)> sum
   => 10

Method 6: eval

Evaluates the Ruby expression(s) in string.

  [26] pry(main)> a = [1,3,4,5]
  => [1, 3, 4, 5]
  [27] pry(main)> eval a.join '+'
  => 13
  [30] pry(main)> a = [1,3,4,5, nil]
  => [1, 3, 4, 5, nil]
  [31] pry(main)> eval a.join '+'
  SyntaxError: (eval):1: syntax error, unexpected end-of-input
  1+3+4+5+

Answer 14

If you feel golfy, you can do

eval [123,321,12389]*?+

This will create a string "123+321+12389" and then use function eval to do the sum. This is only for golfing purpose, you should not use it in proper code.

Answer 15

You can also do it in easy way

def sum(numbers)
  return 0 if numbers.length < 1
  result = 0
  numbers.each { |num| result += num }
  result
end

Answer 16

You can use .map and .sum like:

array.map { |e| e }.sum