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I'm designing a circuit which has to meet the standard IEC 61010-1. It has a transient voltage limitation at the input, so I can calculate my clearances according to section K.3.2.

The surge limitation is redundant (with risk analysis etc. pp.), so I am allowed to reduce clearances in the following circuit. Let's calculate with a working voltage of max. 1000 V and a maximum total voltage limited to 2000 V (working voltage + transient)

I need to measure a high voltage, so at the input, I have a 10 MΩ voltage divider to scale down the input voltage. With several taps to have multiple ranges.

For correct clearance calculation: My working voltage \$U_w\$ should scale down according to the resistance ratios. But what about the transient voltage? Does it scale down too? Or does the working voltage part scale down, but not the “additional voltage” \$U_t\$? Or does \$U_m\$ (which is limited by another circuit) always stay constant going down the resistor divider for this calculation?

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  • \$\begingroup\$ Can you edit the question to include a schematic of how \$U_m\$ is limited by another circuit? At the moment I'm not sure how \$U_m\$ being limited will interact with \$U_w\$. \$\endgroup\$ Commented Aug 7 at 9:49
  • \$\begingroup\$ I added a short text. The limitation in detail works (tested in our lab) and fulfills the requirements of the standard (section K.4) to allow reduction of clearances. \$\endgroup\$ Commented Aug 7 at 10:04

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