The 1940 Rhode Island gubernatorial election was held on November 5, 1940. Democratic nominee J. Howard McGrath defeated incumbent Republican William Henry Vanderbilt III with 55.84% of the vote.
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November 5, 1940
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McGrath: 50–60% 60–70% 70–80% Vanderbilt: 50–60% 60–70% 70–80% Tie: | |||||||||||||||||
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General election
editCandidates
editMajor party candidates
- J. Howard McGrath, Democratic
- William Henry Vanderbilt III, Republican
Other candidates
- Wilfred J. Boissy, Communist
Results
edit| Party | Candidate | Votes | % | ±% | |
|---|---|---|---|---|---|
| Democratic | J. Howard McGrath | 177,937 | 55.84% | ||
| Republican | William Henry Vanderbilt III (incumbent) | 140,480 | 44.08% | ||
| Communist | Wilfred J. Boissy | 257 | 0.08% | ||
| Majority | 37,457 | ||||
| Turnout | |||||
| Democratic gain from Republican | Swing | ||||
References
edit- ↑ Moore, John Leo, ed. (1994). Congressional Quarterly's Guide to U.S. elections. CQ Press. ISBN 9780871879967. Retrieved April 30, 2020.