New answers tagged variable-substitution
21
votes
Accepted
Why arithmetic syntax error in bash causes exit from the function?
POSIX requires that expansion errors exit non-interactive shells (and produce an error message).
A syntax error upon arithmetic expansion is an expansion error
When in POSIX mode like when ...
- 584k
2
votes
Why arithmetic syntax error in bash causes exit from the function?
The problem is that you are using $a and $b inside the $(( … )) expression evaluator:
c=$(($a - $b)) # Wrong (almost always)
What's happening here is that $a and $b are evaluated as variables and ...
- 128k
Top 50 recent answers are included