Regex for sed/awk command

Question

I would like to change the file content which i specified like below.I want to comment out all the lines which contains ".class" except the class name i provide.

@MyClass1.MyClass2(value = {
    Class1.class,
    Class2.class,
    Class3.class,
    Class4.class
})
public class Foo {}

For example if i provide Class2 as parameter to

sed -i -E 's/some_regex/Class2/g'

command,the result should be like this,

@MyClass1.MyClass2(value = {
    //Class1.class,
    Class2.class,
    //Class3.class,
    //Class4.class
})
public class Foo {}

What regex should i use for this?

Answer 1

For a file like this:

$ cat file1
@MyClass1.MyClass2(value = {
    Class1.class,
    Class2.class,
    Class3.class,
    Class4.class
})
public class Foo {}
@MyClass11.MyClass2(value = {
    Class1.class,
    Class2.class,
    Class3.class,
    Class4.class
})
public class Foo2 {}

You can have this result:

$ sed '/@MyClass1.MyClass2(*/,/})/{s|\sClass.*|//&|g; /Class2/{s|//||}}' file1
@MyClass1.MyClass2(value = {
   // Class1.class,
    Class2.class,
   // Class3.class,
   // Class4.class
})
public class Foo {}
@MyClass11.MyClass2(value = {
    Class1.class,
    Class2.class,
    Class3.class,
    Class4.class
})
public class Foo2 {}

Explanation:

'/@MyClass1.MyClass2(*/,/})/ {....} --> range to operate in form /from/,/to/{actions}

{s|\sClass.*|//&|g; --> apply // in all lines starting with whitespace \s and then Class

/Class2/{s|//||} --> remove // for Class2

Tip: In sed we can use any char as a separator for s/replacethis/withthat/ synthax.
I choose | to avoid escaping //

Answer 2

awk '/\.class/ && !/Class2/ {print "//", $0}
     !(/\.class/ && !/Class2/) {print $0}' filename