bash + run script in the loop cycle

Question

we need to run the run.sh on each 10 steps

for x in {1..100} ; do
  sleep 1
  /tmp/run.sh
done

so finally run.sh will run 10 times

how we can do that?

other example ( in this case run.sh will run 20 times )

for x in {1..200} ; do
  sleep 1
  /tmp/run.sh
done

I supposed there are other stuff like sleep 1 that need to be run on all iterations ? — Archemar
– Archemar, Commented Feb 22, 2018 at 14:22

Gilles Quénot · Accepted Answer · 2018-02-22 14:17:14Z

4

You just have to test if the value of x can be divided by 10 :

for x in {0..100} ; do
    if (( x % 10 == 0 ))
    then
        /tmp/run.sh
    fi
    sleep 1
done

Gilles Quénot

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answered Feb 22, 2018 at 14:11

Félicien

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cas · Accepted Answer · 2018-02-22 14:21:48Z

4

This is a job for the modulus (%) operator. For example:

for x in {1..100} ; do
  sleep 1
  [ $((x % 10)) -eq 0 ] && /tmp/run.sh
done

Another example:

$ for i in {1..100} ; do  [ $((i % 10)) -eq 0 ] && echo $i  ; done
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answered Feb 22, 2018 at 14:12

cas

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Kusalananda · Accepted Answer · 2018-02-22 14:17:06Z

2

for (( i = 0; i < 10; ++i )); do
    /tmp/run.sh
    sleep 10
done

If you want to run the script ten times, then do the loop ten times and sleep the appropriate amount of time in-between.

Or, with a parameter determining how many times to run the script:

n=20
for (( i = 0; i < n; ++i )); do
    /tmp/run.sh
    sleep 10
done

answered Feb 22, 2018 at 14:17

Kusalananda♦

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3 Answers 3