Is there is any solution to delete the files based on comparing their modified date with the most recently modified file? The older files need to be deleted with respect to most recent file.
For example, if the last modified date is 09-10-2017, it means the files that are 10 days older need to be deleted. Same if the modified date is changed; the files to be deleted should change accordingly.
With GNU tools:
find . -type f -printf '%T@:%p\0' |
sort -rzn |
awk -v RS='\0' -v ORS='\0' -F: -v d=10 '
NR == 1 {t = $1 - 86400 * d}
$1 < t, 0 {sub(/[^:]*:/, ""); print}' |
xargs -r0 echo rm
(remove the echo when happy).
We're getting find to print 123456.123:./path/to/file<NUL> for each file (with 123456.123 being the last modification time of the files).
We're sorting that numerically (so the newest file comes first) and then using awk to find the ones that are more than 10 days older than the newest file (found in the first record in that sorted list).
I feel below command would help if you are working on Linux based Operating system.
find /path/to/directory/ -mindepth 1 -mtime +7 -delete
+7 = variable which means files older than 7 days will be deleted
Be careful with spaces, quotes to rm.
01-03-2017?