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I'm trying to build a scrip that compare a file inside different 2 dir,then copy them from dir1 to dir2 is it's not exists in the dir2, or overwrite it if its already existed.

I know that i can use diff dir1 dir2 but then how do copy the result over to dir2. because diff command give me result like only in dir1: file1.txt, from my understand that isn't a file itself(right?)

For the overwrite part, i decide to use [ -ot ] command, but again, from my understand the [ -ot ] only can compare with file but not dir?

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rsync works locally and does tests on both file timestamps and file sizes.

rsync --archive /path/to/source/ /path/to/destination/

You may also use rsync on individual files.

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  • -u is the right option for timestamps comparison ? Commented Sep 28, 2017 at 8:41
  • @PrinPuyakul -u will skip files that are newer on the destination end. Without it, rsync will transfer all files whose timestamps (or sizes) are different. Commented Sep 28, 2017 at 8:45
  • I see -a, --archive is what i'm looking for, but I just wonder how can I printout the result from rsync after it successfully execute (like a file name) @Kusalananda Commented Sep 28, 2017 at 13:52
  • @PrinPuyakul You may use -v or --verbose to see what it's doing, and --progress to see it work on bigger files. --stats will give you a summary at the end. Commented Sep 28, 2017 at 13:53
  • I did try --archive, but it will copy everything over to a new dir every tho the file has an older timestamp, what did i do wrong ?_?. from what I understand it NOT suppose to copy older timestamp file over the new one right? Commented Sep 29, 2017 at 6:52
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Why not cp?

\cp -f /path/to/dir1/* /path/to/dir2/
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