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For example, I've a text file having following lines (no. 423 and 424):

    //printf("%d\t %d\t %d\t %d\t %d\t %d\t %d\t %d\t %d\t %d\n",i,c1,c2,c3,c11,c12,c21,c22,c31,c32); //testcells
    printf("%d\t %d\t %d\t %d\t %d\t %d\t %d\t %d\t %d\t %d\t %d\t %d\t %d   \n",i,r1,r2,r3,r11,r22,r33,r44,r55,r66,r77,r88,r99); //testnodes

Now, suppose I want to remove // in the 423th line i.e characters of column 5 and 6 form 423th line. And simultaneously, suppose I want to add // in 424th line in columns 5 and 6 such that expected output should be

    printf("%d\t %d\t %d\t %d\t %d\t %d\t %d\t %d\t %d\t %d\n",i,c1,c2,c3,c11,c12,c21,c22,c31,c32); //testcells
    //printf("%d\t %d\t %d\t %d\t %d\t %d\t %d\t %d\t %d\t %d\t %d\t %d\t %d   \n",i,r1,r2,r3,r11,r22,r33,r44,r55,r66,r77,r88,r99); //testnodes

How do I do that? (preferably with sed or awk)

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1 Answer 1

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One way:

sed -e '423s!//!!; 424s!printf!//&!' < input > output

This assumes that the first // on line 423 is the one you want to remove, and that it's the printf on line 424 that you want to comment out.

To specifically update based on the columns:

sed -e '423s!^\(....\)//!\1!; 424s!^\(....\)!\1//!' < input > output
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