a script to replace mkdir -p command

Question

I'm writing a script that replaces the mkdir -p command. Here is what I have so far:

#!/bin/sh  

n=1;
max=50;
while [ "$n" -le "$max" ]; do
mkdir "s$n"
n='expr "$n" + 1';
done

I should be able to then use this script to type in aaa/bbb/ccc and it'll make these directories.

Which -p "command" are you referring to? Can you provide input and expected output? What does not work in what you have thus far tried? — DopeGhoti
– DopeGhoti, Commented Dec 9, 2016 at 18:07
alias mkdir='mkdir -p' if all you're trying to do is save yourself some typing. — user4443
– user4443, Commented Dec 9, 2016 at 18:15

Kamaraj · Accepted Answer · 2016-12-09 18:20:09Z

3

execute the script as below.

./script.sh abc/def/ghi/jkl

#!/bin/bash

DIR_LIST=${1}

IFS=/
for DIR_NAME in ${DIR_LIST}
do
    mkdir ${DIR_NAME}
    cd ${DIR_NAME}
done

answered Dec 9, 2016 at 18:20

Kamaraj

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@KingBoi If you are satisfied and this solve your question, you should consider to take a minute to thanks Kamaraj by accepting his answer.

andreatsh
– andreatsh

2016-12-09 21:46:19 +00:00
Commented Dec 9, 2016 at 21:46
@KingBoi And upvoting!

DepressedDaniel
– DepressedDaniel

2016-12-10 01:27:42 +00:00
Commented Dec 10, 2016 at 1:27

Add a comment |

score 1 · Accepted Answer · 2016-12-19 00:37:03Z

1

Using a recursive function:

#!/bin/bash
mkdir_p() {
    local path=$1
    local parent=${path%/*}
    [[ ${path} != /* ]] && parent=${PWD}/${parent}
    [[ ! -d $parent ]] && mkdir_p "${parent}"
    [[ ! -d $path ]] && mkdir "${path}"
}
mkdir_p "${1}"

edited Dec 19, 2016 at 0:37

answered Dec 18, 2016 at 3:29

user14755

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