Earthquake kills more than 3,000 in S. Asia [AP Wire]. Special triple-chocolate brownie cake points (a la
jennuine's recipe) go to India for unexpected generosity to their long-time enemies. Let us follow their example.
What I learned today:1) The instantaneous rate of change for any real x-value a in the function f(x)=bx^2 when b is a real number is 2ba.
I apologize that there is only one item on this list; it's Saturday. In penance I will prove the above statement. Ready?
Assume that the instantaneous rate of change m at any point (a,f(a)) equals the limit as h approaches 0 of [f(a+h) – f(a)]/h when a is any given x-value, a+h is another x-value, h is the interval between them, and f(x) is any given function. (This equation is the one used to find average ROCs between two points in a function, which is essentially what we will be doing, only that the two points we are working with in this case, a+h and a, are actually the same point being used twice and only pretending to be different. The interval between them, h, will be zero, which is why they're the same.)
(To make things simpler for me, and because I like the letter P and it gets slighted in math, we will use (P) as shorthand for lim
(h-->0). This is sort of unmathematical; sorry.)
If (P) [f(a+h) – f(a)]/h = m (inst. ROC), and f(x)=bx^2, then m=(P) [b(a+h)^2 – ba^2]/h. (Here, we substituted (a+h) and (a) in for x in the second equation.)
m=(P) (ba^2 + 2bah + bh^2 – ba^2)/h. (We used FOIL and the distributive property to clear the parentheses in the first part of the numerator.)
m=(P) (
ba^2 + 2bah + bh^2
– ba^2)/h. (The terms ba^2 and –ba^2 canceled each other out to equal 0.) So, P=(2bah + bh^2)/h.
m=(P) h(2ba + bh)/h. (We reversed the distributive property to factor h out of the numerator.)
m=(P)
h(2ba + bh)/
h. (The h in the numerator and the h in the denominator canceled each other out to equal 1.)
So, m=(P) 2ba + bh, or, m=lim
(h-->0) 2ba + bh. (Are you still following?)
In order to solve a limit, we plug in the number that h approaches every time h appears in the accompanying equation. In this case, the number that h approaches is 0.
So, m=2ba + b(0), or just m=2ba. In English, that means the instantaneous rate of change for any x-value a in the equation f(x)=bx^2 when b is a real number equals 2ba. QED. (Do I get to say that? Or do you have to be a physicist?)
Effectively, this means that when you have a parabola, the slope at any given point is just the coefficient of x^2 in the equation, times the x-value of the point, times two. (i.e. The point (5,75) in the function f(x)=3x^2 has a slope of 30 because 30=5*2*3.)
(Take that, calculus. I will eat you.)
(I learned some new HTML on Thursday, but I'll spare you that, even though it is almost as fun as math and perhaps even moreso if you play with background colours. It feels weird, having everything I have learned about HTML in the last four years translated into about ten pages of a single textbook. I am officially no longer any smarter than anyone in my computer class. Having entered the class actually knowing how to use a computer no longer sets me apart. [OMG seriously, did I tell you we learned that you can have TWO PROGRAMS OPEN AT ONCE? And you can change by CLICKING ON THEIR NAMES ON THE BAR AT THE BOTTOM? I bet you didn't know that, huh? Incredible.])