Javascript - Function Parameter As Variable

Question

I've searched a bit for this answer, so here is what I'm trying to do - if possible

function foo(variable){

If I call the function, how would I go about passing that parameter as a variable?

function foo(9){
    var stuff = 9;

//then pass variable to rest of script

Here is the whole code:

function ajaxgetter(variable) {
    var stuff = variable;
    var mygetrequest = new ajaxRequest();
    mygetrequest.onreadystatechange = function() {
        if (mygetrequest.readyState == 4){
            if (mygetrequest.status == 200 || window.location.href.indexOf("http") == -1){
                document.getElementById("result").innerHTML = mygetrequest.responseText;
            } else {
                alert("An error has occured making the request");
            }
        }
    }

    var namevalue = encodeURIComponent(document.getElementById("name9"+stuff).value);
    var agevalue = encodeURIComponent(document.getElementById("age9"+stuff).value);
    var utvalue = encodeURIComponent(document.getElementById("ut9"+stuff).value);
    document.getElementById("result").innerHTML = "<center><b>Loading...</b></center><br><center><img src='images/ajax-loader1.gif' /></center>";
    mygetrequest.open("GET", "newdealerfinder.php?location="+namevalue+"&distance="+agevalue+"&ut="+utvalue1"&r="+ Math.random(), true)mygetrequest.send(null);
}

Onclick event (PHP):

$javacounter = 1;
if($miles1 > 2) {
                echo "<form action='' method='get' />
                <input type='hidden' value='$city->lat,$city->lng' id='name9$javacounter' name='name9$javacounter' />
                <input type='hidden' value='$currentunixtime' id='ut9$javacounter' name='ut9$javacounter' />
                <input type='hidden' value='$distance' id='age9$javacounter' name='age9$javacounter' />
                <input type='button' value='Coming Soon' onClick='ajaxgetter($javacounter)' />
                </form>";
                $javacounter++;
            }

Location of script: Here

I don't understand what you're trying to do. Do you have a complete code example? — Jared Farrish
– Jared Farrish, Commented Oct 27, 2011 at 22:41
By writing function foo (bar) {..., you are already declaring the function arguments, so when you call foo(9), bar will have value 9 and it exists as a local variable in that function scope (accessible within the scope and inner functions) . — Idriz Šunja
– Idriz Šunja, Commented Oct 27, 2011 at 22:43

Jared Farrish · Accepted Answer · 2011-10-27 23:41:50Z

2

If this is your function definition

function foo(variable){
    var stuff = variable;
    alert(stuff);
    return stuff;
}

Then you call it and pass a value like so

var x = foo(9); //will alert 9
// use x..

// then pass variable to rest of script

Not sure what the "rest of script" is. But if you're looking for this to be accessed outside the function, you need to do some research on Javascript variable scope and using globals (as opposed to passing arguments).

Tho you can return a variable from your function in order to use it throughout the script as well. I updated the code the show that...

edited Oct 27, 2011 at 23:41

Jared Farrish

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answered Oct 27, 2011 at 22:41

Nick Rolando

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3 Comments

Go3Team Over a year ago

I added something similar to that in my edited code above, and it doesn't seem to work. For whatever reason, onclick isn't firing.

Nick Rolando Over a year ago

@Go3Team I don't see you setting an onclick event

Nick Rolando Over a year ago

@Go3Team not sure. syntax seems fine. are you positive its not firing? tried setting alert("hello"); at the top of ajaxgetter()?

Ibuprofen · Accepted Answer · 2011-10-27 22:53:50Z

1

I think you are trying to get the result from the function call and use it in the rest of the script?

var foo = function (variable) {
    // do some stuff with variable
    return variable;
}

var result = foo(9);
// do whatever with result in rest of script

answered Oct 27, 2011 at 22:53

Ibuprofen

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