Reshaping an array in Python

Question

I am trying to reshape I1 from (7,2) to (1,7,2) by means of a variable k which has the shape of old I1. But I get an error. Is there a way to do it?

import numpy as np

I1= np.array([[0, 1],
              [0, 2],
              [1, 3],
              [2, 3],
              [2, 5],
              [3, 6],
              [5, 6]])
k=I1.shape
I1=I1.reshape(1,k)

The error is

<module>
    I1=I1.reshape(1,k)

TypeError: 'tuple' object cannot be interpreted as an integer

you don't want to reshape, you want to add dim, try this : I1[None,...] — Mahdi F.
– Mahdi F., Commented Jun 27, 2022 at 15:16
Best way to do this is, as say @I'mahdi adding a new dimension I1[None,:,:] will give you a new array with an aditional axis with length 1. It's the same as I1[np.newaxis,:,:] (new axis it's actually None but in a pretty way to be clear that you are adding an axis). Last but less recommendable is to create a list with I1 and then create array agayn (more computation, less pretty, slower but a posible way) np.array( [I1] ) — Ulises Bussi
– Ulises Bussi, Commented Jun 27, 2022 at 15:21

Nam · Accepted Answer · 2022-06-27 15:21:09Z

1

Because k is a tuple with 2 elements, when it's passed to a function, an asterisk * is needed.

Instead of I1 = I1.reshape(1, k), try I1 = I1.reshape(1, *k)

answered Jun 27, 2022 at 15:21

Nam

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