I'm trying to check an objects every entry's key and value in a if condition, but i cannot understand my result. What is the problem? Why is an undefined not false with "??" ?
const object = {undefined: "foo", B: "Bazz"}
console.log(Object.entries(object).every(([key, value]) => !!key && !!value))
//true
const object2 = {undefined: null, B: "Bazz"}
console.log(Object.entries(object2).every(([key, value]) => !!key && !!value))
//false
You cannot actually set the key to undefined. When you do { undefined: "foo" }, you are actually setting the key to the string "undefined". It is essentially the same as { "undefined": "foo" }
!!"undefined" && !!"foo" => true && true => true because non-empty strings are truthy
!!"undefined" && !!null => true && false => false because null is falsy
The propertie names of objects are strings or Symbol. To check the value, you could take an array of unwanted strings and check with includes.
const
check = object => Object
.entries(object)
.every(([key, value]) => !['', 'null', 'undefined'].includes(key) && value);
console.log(check({ a: "foo", B: "Bazz" }));
console.log(check({ undefined: "foo", B: "Bazz" }));
console.log(check({ undefined: null, B: "Bazz" }));
'undefined'is a string. btw, why do you expect a different result?