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I need to remove the empty string from the array inside another array and I need to return the whole array without an empty string, can anyone help me with this, array is below

const testArr =  [
        {
            code: 'size',
            name: 'Size',
            options: ['small', "", "", "large"],
          
        },
        {
            code: 'color',
            name: 'COlor',
            options: ['black', "", "", "red"],
          
        },
    ]

I need result like this(without empty string)

[
    {
        code: 'size',
        name: 'Size',
        options: ['small', "large"],

    },
    {
        code: 'color',
        name: 'COlor',
        options: ['black', "red"],

    },
]
2
  • use .filter() method to filter out the empty strings: array.filter(s => s.trim().length > 0) Commented Nov 4, 2020 at 11:53
  • but .filter() is returning only options, I need a whole array without empty string @Yousaf Commented Nov 4, 2020 at 11:54

1 Answer 1

1

Use .map() method to iterate over testArr and transform its elements and use .filter() method on the options array in each object, to filter out the empty strings.

const testArr = [
  { code: 'size', name: 'Size', options: ['small', "", "", "large"] },
  { code: 'color', name: 'COlor', options: ['black', "", "", "red"] }
];

const result = testArr.map(obj => {
  obj.options = obj.options.filter(s => s.trim().length > 0);
  return obj;
});

console.log(result);

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