How can I loop over and check if one or some arrays inside of a JavaScript Object is empty?
i.e.
const store = {
shirts : [],
shoes: ['nike', 'puma', 'addidas']
hats: [],
jerseys: ['barcelona', 'milan', 'arsenal']
}
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5 Answers
Get the values of the object using Object.values(). Check if at least one of them is an array with the length of 0 using some and Array.isArray()
const store = {
shirts: [],
shoes: ['nike', 'puma', 'addidas'],
hats: [],
jerseys: ['barcelona', 'milan', 'arsenal']
}
console.log(
Object.values(store).some(v => Array.isArray(v) && v.length === 0)
)
Comments
If you just want to know whether there is an empty array, val will be true if one of the arrays is empty, otherwise false.
val = Object.keys(store).some(key => store[key].length === 0)
Comments
const store = {
shirts : [],
shoes: ['nike', 'puma', 'addidas'],
hats: [],
jerseys: ['barcelona', 'milan', 'arsenal']
}
for(let item in store){
if(store[item].length == 0)
console.log(item)
}Each empty item will be logged to console
Comments
Here's a one liner:
const main = o => Object.entries(o).some(([k,a])=>!a.length);
console.log(
main({x: [1,2,3],y: [123],}), // false
main({x: [1,2,3],y: [],}), // true
main({x: [],y: [],}), // true
);
Comments
If you want to get the empty keys than you can use filter method
const store = {
shirts : [],
shoes: ['nike', 'puma', 'addidas'],
hats: [],
jerseys: ['barcelona', 'milan', 'arsenal']
}
const emptyKeys = Object.keys(store).filter((key) => {
if (store[key].length == 0) {
return key;
}
});
console.log(emptyKeys);
