bash script to run command-line java program

Question

Currently I run my program like this:

java program arg1 arg2 arg3...

There are a variable number or arguments. Is there some BASH script or something I can package with my program to allow me to run it just like

program arg1 arg2 arg3

and continue to allow me to have variable arguments.

I just care about Unix systems.

I'm sorry for this simple question: I'm a Java developer, not a BASH scriptor.

Paŭlo Ebermann · Accepted Answer · 2011-04-16 21:12:07Z

10

Here:

#!/bin/bash

java program "$@"

Or if you want the bash to exit when java is called, use this:

#!/bin/bash

exec java program "$@"

(This replaces the bash process with the java process instead of waiting until java returns.)

answered Apr 16, 2011 at 21:12

Paŭlo Ebermann

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Comments

chrisaycock · Accepted Answer · 2011-04-16 21:11:03Z

2

Just use an alias:

alias program='java program'

answered Apr 16, 2011 at 21:11

chrisaycock

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Since he wants to pass arguments, I doubt aliases can be used. A function would be needed.

@qwerty Arguments very much can be used with aliases. Try it yourself.

Common way of doing it, is using a batch file.

@gyger The OP is using bash in Unix. Batch files are for Windows.