How to convert and Integer to an 64-bit byte representation in python

Question

I am trying to convert an integer. E.g 3063294273, to a 64-bit big endian encoded byte representation. So for example if I have a value = 1 my output should be
0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x01

What would be the best approach to do this in python?

Edit: I saw the other question provided in Convert a Python int into a big-endian string of bytes. But in the other question, the author was not asking for a specific size of the output. Which is important for my problem.

Your example shows 128 bits (16 instances of 8-bit (two hex digit)) values. — Tom Karzes
– Tom Karzes, Commented Jun 8, 2019 at 10:37
Possible duplicate of Convert a Python int into a big-endian string of bytes — Arkistarvh Kltzuonstev
– Arkistarvh Kltzuonstev, Commented Jun 8, 2019 at 10:38
I dont see the duplicate? In the provided other question, the author was not asking for a specific size of the output. — JustPlayin
– JustPlayin, Commented Jun 8, 2019 at 11:54

Ry- · Accepted Answer · 2019-06-08 10:36:26Z

1

int.to_bytes

>>> value = 1
>>> value.to_bytes(8, 'big')
b'\x00\x00\x00\x00\x00\x00\x00\x01'

(Your sample output is 128 bits, so if you meant that, use 16.)

answered Jun 8, 2019 at 10:36

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