Numpy array without for loop

Question

array = np.empty(8,4)

for I in range(8):
   array[I] = I

Can this be implemented without for loop. I would like know other approaches

array = np.empty(8,4)
for I in range(8):
   array[I] = I 

[0,0,0,0]
[1,1,1,1]
    .
    .
    .
[7,7,7,7]

creating 8 rows and 4 columns 2 dimensional array and assigns 0 for every cell.Syntax typo: np.empty((8,4)) — user10812455
– user10812455, Commented Jan 29, 2019 at 17:37

ernest_k · Accepted Answer · 2019-01-29 17:46:05Z

1

One easy way is to just use np.repeat:

array = np.repeat(np.arange(8), 4).reshape(8, 4)

array([[0, 0, 0, 0],
       [1, 1, 1, 1],
       [2, 2, 2, 2],
       [3, 3, 3, 3],
       [4, 4, 4, 4],
       [5, 5, 5, 5],
       [6, 6, 6, 6],
       [7, 7, 7, 7]])

answered Jan 29, 2019 at 17:46

ernest_k

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