Am trying the following
Input:
myarray1=['Tag A','Tag B','Tag C']
myarray2=['Tag B','Tag C']
myarray3=['Tag A','Tag D']
Output:
outputArray=['Tag A','Tag B','Tag C','Tag D']
The output array should conatin the unique values from the input arrays.
Am trying this in typescript but not able to find the unique values from input array. Any suggestions how to achieve this in optimal way
Pass the merged arrays into a Set and spread that set into results array
myarray1=['Tag A','Tag B','Tag C']
myarray2=['Tag B','Tag C']
myarray3=['Tag A','Tag D']
const uniques = [...new Set(myarray1.concat(myarray2,myarray3))]
console.log(uniques)You can easily do it with ES6 Spread and Set
myarray1=['Tag A','Tag B','Tag C']
myarray2=['Tag B','Tag C']
myarray3=['Tag A','Tag D']
const uniqueArr = [...new Set([...myarray1,...myarray1,...myarray3])];
console.log(uniqueArr)
destructuring here?Very simple, only using array functions, first you conctainate all of the arrays, then you use the fitler function to simply ensure that there's only ever unique values.
const myarray1 = ['Tag A', 'Tag B', 'Tag C'],
myarray2 = ['Tag B', 'Tag C'],
myarray3 = ['Tag A', 'Tag D'];
const mergedArray = Array.concat(myarray1, myarray2, myarray3).filter((s, i, array) => array.indexOf(s) === i);
console.log(mergedArray);You can do it with reduce Set and spread operator.
let arr1=['Tag A','Tag B','Tag C']
let arr2=['Tag B','Tag C']
let arr3=['Tag A','Tag D']
let arr = [arr1,arr2,arr3]
let op = [...new Set( arr.reduce((o,c)=>o.concat(c),[]))];
console.log(op);