Pythonic way to print 2D list -- Python

Question

I have a 2D list of characters in this fashion:

a = [['1','2','3'],
     ['4','5','6'],
     ['7','8','9']]

What's the most pythonic way to print the list as a whole block? I.e. no commas or brackets:

123
456
789

Answer 1

There are a lot of ways. Probably a str.join of a mapping of str.joins:

>>> a = [['1','2','3'],
...          ['4','5','6'],
...          ['7','8','9']]
>>> print('\n'.join(map(''.join, a)))
123
456
789
>>>

Answer 2

Best way in my opinion would be to use print function. With print function you won't require any type of joining and conversion(if all the objects are not strings).

>>> a = [['1','2','3'],
...      ['4', 5, 6],   # Contains integers as well.
...      ['7','8','9']]
...

>>> for x in a:
...     print(*x, sep='')
...
...
123
456
789

If you're on Python 2 then print function can be imported using from __future__ import print_function.

Answer 3

I'm a beginner learner, so please take my post with a few spoons of salt. But I have a better idea ( which includes printing a list with string+ integers)

D2List=[[1,2,3],[4,"Bingo",5],[6,7,8]]

for x,y,z in D2List:
    print ("x,y,z")

I got it working: https://github.com/Bahaa2468/Python/blob/22e6cfc9b478f9336ef0be283e2693c40f13d538/Bingo%20Game.Generator.py

Answer 4

Like this:

import os

array = [['1','2','3'],
         ['4','5','6'],
         ['7','8','9']]
print(os.linesep.join(map(''.join, array)))

Answer 5

If you're looking for Pythonic then you surely need a generator comprehension:

print('\n'.join(''.join(i) for i in array))