I am new to Python (30 minutes). I want to know how to identify whether the number is an integer or a string, and proceed with the result using if else.
My code is:
number = input("enter the number \n")
integer = int(number)
if integer.is_integer():
if integer > 0:
print("positive ", integer)
elif integer < 0:
print("Negative ", integer)
else:
print("Number is", integer)
else:
print("Enter integer value")
number = input("enter the number \n")
try:
integer = int(number)
if integer > 0:
print "positive", integer
elif integer < 0:
print "Negative", integer
else:
print "Number is", integer
except ValueError:
print("Enter integer value")
except blocks as close to the cause of error as possible.
Python provides doc-typing feature which means no matter if a value defined as a String or Number. So you must only check if the value conforms numerical properties or not using isnumeric(). This method returns true if all characters in the string are numeric, false otherwise.
str = u"hello100";
print str.isnumeric() #returns false
str = u"123900";
print str.isnumeric() #returns true
"-123".
integer = int(number)will fail anyway withValueError. You can wrap it in atry/exceptblock.intis able to parse the numberis_integerwill always returnTrue...