I currently have this problem where I cannot seem to find an answer specific to my problem.
Array1 = ["item1", "item2", "item3", "item4", "item5"]
Array2 = ["item2", "item5"]
I am looking to use the information from array2 to find within array1.
An example for this to output
Array1 has item2 and is at Array1[1]
If anyone can help me, thank you.
Array2.forEach((e) => {
const indexOfE = Array1.indexOf(e)
if (indexOfE > -1) {
console.log(`Array1 has ${e} and is at Array1[${indexOfE}]`)
}
})
You can have a look at forEach, indexOf, and template literals to help you understand this code.
Edit
Answering the question in the comments, if you want to check the elements in Array1 that contain elements of Array2 as substrings, then you can:
Array2.forEach((e) => {
Array1.forEach((f, i) => {
if (f.toLowerCase().includes(e)) {
console.log(`Array1 has ${e} and is at Array1[${i}]`)
}
})
})
Check String.prototype.includes and this answer for details on finding substrings in another String.
Array2 search more in terms of find the word specifically regardless of how it is within Array1? More like an includes or contains method. For example say it was " largeitem1 " and Array2 still had "item1"
If you only want to know Array1 contains an element from Array2 then iterate over Array2 calling indexOf for each element:
Array2.map((el => {
if (Array1.indexOf(el) !== -1) {
console.log('Array 1 contains ' + el);
}
}));
.forEach() is a better choice than .map(). The result is the same, but .map() implies that you are, well, mapping something. Which you're not.
This is the code:
var Array1 = ["item1", "item2", "item3", "item4", "item5"];
var Array2 = ["item2", "item5"];
for (var i = 0; i <Array2.length; i++) {
if (Array1.indexOf(Array2[i])>-1) {
console.log("Array1 has "+Array2[i]+" and is at Array1["+Array1.indexOf(Array2[i]) +"]")
}
}
You could Ramdajs to find intersection of two arrays as follows
const Array1 = ["item1", "item2", "item3", "item4", "item5"];
const Array2 = ["item2", "item5"];
const res = R.intersection(Array1, Array2);
console.log(res);
here is the code repel
The same could be achieved using lodash
const Array1 = ["item1", "item2", "item3", "item4", "item5"];
const Array2 = ["item2", "item5"];
const res = _.intersection(Array1, Array2)
console.log(res);
here is the jsfiddle for lodash.
or you could use the includes method of the array to do the same
const Array1 = ["item1", "item2", "item3", "item4", "item5"];
const Array2 = ["item2", "item5"];
const res = Array1.filter(curr=>Array2.includes(curr));
console.log(res);
"item5"? Can the same string potentially occur more than once inArray1? What have you tried so far? I'm thinking a simpleforloop overArray2with a call toArray1.indexOf()would get the job done easily enough. If your question is "Please code the whole thing for me" what you really want is a JS tutorial - there are links to some on the SO JS info page.