502

We can access array elements using a for-of loop:

for (const j of [1, 2, 3, 4, 5]) {
  console.log(j);
}

How can I modify this code to access the current index too? I want to achieve this using for-of syntax, neither forEach nor for-in.

0

12 Answers 12

793

Use Array.prototype.keys:

for (const index of ["a", "b", "c", "d", "e"].keys()) {
  console.log(index);
}

If you want to access both the key and the value, you can use Array.prototype.entries() with destructuring:

for (const [index, value] of ["a", "b", "c", "d", "e"].entries()) {
  console.log(index, value);
}

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10 Comments

In case someone wonders, I tested for-of with .entries() and it's twice as slow compared to .forEach(). jsperf.com/for-of-vs-foreach-with-index
@K48 nice to know, use "reversed for-loop" if you want to have the fastest in es: incredible-web.com/blog/…
Unfortunately, I need to yield from inside a nested loop. Can't use forEach, because the function creates scope problems for the yield keyword. But I need access to the index for my use case, so... basic old ;; loop it is, I guess.
@KyleBaker And what's wrong with a for-of loop with .entires()?
Instead reverse loop you may cache length jsperf.com/reverse-loop-vs-cache. For-of usefull for iterable processing when you able to process stream without creating big arrays in RAM. Loop speed wouldn't be bottleneck since you will have I/O latency in such cases.
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436

Array#entries returns the index and the value, if you need both:

for (let [index, value] of array.entries()) {

}

7 Comments

With TypeScript: 'TS2495: Type IterableIterator is not an array type or a string type'. Seems like this will be solved: github.com/Microsoft/TypeScript/pull/12346
Also Internet Explorer not supported.
Not nice. Throws an error e.g. with document.styleSheets[0].cssRules.entries() or even document.styleSheets.entries() and probably many other DOM iterable structures. Still have to use _.forEach() from lodash
@Steven: If you don't need the index, you can just do for (var value of document.styleSheets) {}. If you do need the index you can convert the value to an array first via Array.from: for (let [index, value] of Array.from(document.styleSheets)) {}.
That's nice! Array.from is FTW
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155

In this world of flashy new native functions, we sometimes forget the basics.

for (let i = 0; i < arr.length; i++) {
    console.log('index:', i, 'element:', arr[i]);
}

Clean, efficient, and you can still break the loop. Bonus! You can also start from the end and go backwards with i--!

Additional note: If you're using the value a lot within the loop, you may wish to do const value = arr[i]; at the top of the loop for an easy, readable reference.

11 Comments

By the way the condition should look like this -> for (let i = 0; i < arr.length; i++) without the (-1) or it will not loop throughout all the elements of the array.
You can still break a for-of and for (let [index, value] of array.entries()) is far easier to read. Going backwards is as easy as adding .reverse().
This does not answer the question in any way. It would be nice in a comment (basics are always important), but not here.
I think this is a perfectly acceptable answer to this question. It will never be the accepted answer but it has helped a few dozen people or more who have searched for this question. This is what SO is for.
The simple for loop is ~8 times faster than the for of array.entries(). jsbench.me/6dkh13vqrr/1
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28

In a for..of loop we can achieve this via array.entries(). array.entries returns a new Array iterator object. An iterator object knows how to access items from an iterable one at the time, while keeping track of its current position within that sequence.

When the next() method is called on the iterator key value pairs are generated. In these key value pairs the array index is the key and the array item is the value.

let arr = ['a', 'b', 'c'];
let iterator = arr.entries();
console.log(iterator.next().value); // [0, 'a']
console.log(iterator.next().value); // [1, 'b']

A for..of loop is basically a construct which consumes an iterable and loops through all elements (using an iterator under the hood). We can combine this with array.entries() in the following manner:

array = ['a', 'b', 'c'];

for (let indexValue of array.entries()) {
  console.log(indexValue);
}


// we can use array destructuring to conveniently
// store the index and value in variables
for (let [index, value] of array.entries()) {
   console.log(index, value);
}

Comments

14

You can also handle index yourself if You need the index, it will not work if You need the key.

let i = 0;
for (const item of iterableItems) {
  // do something with index
  console.log(i);

  i++;
}

Comments

6

Another approach could be using Array.prototype.forEach() as

Array.from({
  length: 5
}, () => Math.floor(Math.random() * 5)).forEach((val, index) => {
  console.log(val, index)
})

Comments

4

in html/js context, on modern browsers, with other iterable objects than Arrays we could also use [Iterable].entries():

for(let [index, element] of document.querySelectorAll('div').entries()) {

    element.innerHTML = '#' + index

}

1 Comment

Yes this works, whereas other mentioned above by @Steven Pribilinskiy other DOM methods return objects that don't have an entries method for them.
4

Just create a variable before the loop and assign an integer value.

let index = 0;

and then use addition assignment operator into the loop scope

index += 1;

That's It, check the below snippet example.

let index = 0;
for (const j of [1, 2, 3, 4, 5]) {
  console.log('index ',index);
  index += 1;
}

Comments

2

For those using objects that are not an Array or even array-like, you can build your own iterable easily so you can still use for of for things like localStorage which really only have a length:

function indexerator(length) {
    var output = new Object();
    var index = 0;
    output[Symbol.iterator] = function() {
        return {next:function() {
            return (index < length) ? {value:index++} : {done:true};
        }};
    };
    return output;
}

Then just feed it a number:

for (let index of indexerator(localStorage.length))
    console.log(localStorage.key(index))

Comments

2

You can try making use of indexOf menthod inside for of... loop

let arrData = [15, 64, 78]
for (const data of arrData) {
  console.log("data value", data, "index of data ", arrData.indexOf(data));
}

1 Comment

This works only on unique elements, and has O(n^2) complexity :(
0

Also you can use JavaScript to solve your problem

iterate(item, index) {
    console.log(`${item} has index ${index}`);
    //Do what you want...
}

readJsonList() {    
    jsonList.forEach(this.iterate);
    //it could be any array list.
}   

Comments

-3

es6 for...in

for(const index in [15, 64, 78]) {                        
    console.log(index);
}

4 Comments

The question is asking about a for...of loop not a for...in
for...in is part of the original ECMAScript specification (i.e."es1") . Also, note that for...in is meant for iterating over object properties. While it can iterate over arrays, it may not do so in the expected order. See more in the MDN documentation
this is a good answer for the aim of the question. Which is about "array" itteration.
no it's not a good answer, since the question was specific about for...of loop and not just general itteration...

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