Java XML dynamic parser

Question

I'm looking for a simple solution.

I have a xml file:

<properties>
    <property>
        <class>java.lang.String</class>
        <value>String value...</value>
    </property>
    <property>
        <class>java.lang.Boolean</class>
        <value>true</value>
    </property>
    <!-- ... others java lang wrapper class -->
</properties>

I would like to do a dynamic parser.

I know that I can read the xml with org.w3c.dom.* and org.w3c.dom.Node.getTextContent() I can get the value of the tag.

Class<?> clazz = Class.forName(classTextContent);
// How to convert value to specific clazz?
// if/else (clazz)? Does not look a nice answer.

Any suggestion?

[Edited] By reflection:

The variable "clazz " is a java.lang.Class, right? How can I convert textContent value (in String) to any wrapper type?

Object objectValue = null;
Class<?> clazz = Class.forName(nodeClass.getTextContent());
String value = nodeValue.getTextContent();
if (clazz.equals(Boolean.class) { objectValue = Boolean.valueOf(value) }

valueOf could be a generic method that I could call using reflection... Integer, Float, Boolean, Long, Double support valueOf.

Another way?

Reflection is your answer: docs.oracle.com/javase/tutorial/reflect — eric.m
– eric.m, Commented Aug 20, 2015 at 19:21

eric.m · Accepted Answer · 2015-08-20 19:28:46Z

0

Object object = YourClass.class.getConstructor(new Class<?>[]{}).newInstance();

// if you want to use a constructor, let's say, for YourClass(int name, int id)

Object object = YourClass.class.getConstructor(new Class<?>[]{int.class, int.class}).newInstance(desiredName, desiredId);

answered Aug 20, 2015 at 19:28

eric.m

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2 Comments

Marcos Oto Over a year ago

Emd4600 please take a look into my edited question. Thanks

eric.m Over a year ago

Not as far as I know. You could use this stackoverflow.com/a/16172206/3779214, making the user specify the field to fill with the value.

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