Using arrays in loops

Question

I've tried to use an array in a loop (in PHP) so that I can display 5 random values. But the problem is that the program doesn't work and nothing appears on the browser.

What's wrong with this code? Have I missed something?

<?php

$my_array = array('Mohammed', 'Khaled', 'Nasser', 'Yasser', 'Ahmed', 'Badr', 'Ibrahim', 'Ali', 'Turkey', 'Abdullah', 'Bandar', 'Omar', 'Saleh', 'Saeed', 'Salem');
$random_array = array_rand($my_array, 5);

for ($x==0 ; $x==4 ; $x++) {
    echo $my_array[$random_array[$x]] . "</br>";
}

?>

$x == 0 is a comparison, you want an assignment $x = 0, the loop condition should be a comparison $x < 5 — Mithrandir
– Mithrandir, Commented Jun 2, 2015 at 10:13

Narendrasingh Sisodia · Accepted Answer · 2015-06-02 10:20:24Z

2

Update your for loop as

for ($x=0 ; $x<=4 ; $x++) {
    echo $my_array[$random_array[$x]] . "</br>";
}

You need to learn how for loop works

1. $x=0;//Initializing value of $x 
 2. $x<=4;//Loop till the value of $x is less than or equal to 4 
 3. $x++;//Increment the value of $x by one i.e. $x= $x+1

edited Jun 2, 2015 at 10:20

answered Jun 2, 2015 at 10:12

Narendrasingh Sisodia

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Comments

Karl · Accepted Answer · 2015-06-02 10:13:54Z

0

You could do it more simple. Also == is for comparison not assignment.

foreach(array_rand($my_array, 5) as $item) {
    echo $item . '<br>';
}

answered Jun 2, 2015 at 10:13

Karl

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Comments

Jasper · Accepted Answer · 2015-06-02 10:16:23Z

0

This will work 

<?php

$my_array = array('Mohammed', 'Khaled', 'Nasser', 'Yasser', 'Ahmed', 'Badr',   'Ibrahim', 'Ali', 'Turkey', 'Abdullah', 'Bandar', 'Omar', 'Saleh', 'Saeed', 'Salem');
$random_array = array_rand($my_array, 5);

for ($x=0 ; $x<6 ; $x++) {
echo $my_array[$random_array[$x]] . "</br>";
}

?>

answered Jun 2, 2015 at 10:16

Jasper

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1 Comment

Karl Over a year ago

$x < 6 should be $x < 5

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