Javascript parse nested JSON objects

Question

I am new to javascript and I am trying to parse and manipulate the data below but not too sure how to go about it. Can anyone help please?

JSON Data

{
    "2009-01": {
        "bbcfour": 324,
        "bbcnews24": 1075,
        "bbcone": 940,
        "bbcthree": 441,
        "bbctwo": 1040,
        "cbbc": 898,
        "cbeebies": 1343
    },
    "2009-02": {
        "bbcfour": 295,
        "bbcnews24": 958,
        "bbcone": 904,
        "bbcthree": 434,
        "bbctwo": 1038,
        "cbbc": 793,
        "cbeebies": 1246
    }}

JavaScript

<!DOCTYPE html>
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en">
<head>
<meta charset="utf-8" />
<meta http-equiv="content-language" content="en" />
<meta http-equiv="Content-Type" content="UTF-8" />
<meta http-equiv="X-UA-Compatible" content="IE=edge" />
<meta name="viewport" content="width=device-width, initial-scale=1.0, maximum-scale=1.0, user-scalable=0" />
<link href="main.css" media="all" rel="stylesheet" type="text/css" />
</head>
<body>
<script src="jquery-2.1.1.js"></script>
<script>
$.getJSON('data.json', function (data) {
    console.log(data);
});
</script>
</body>
</html>

You don't have to parse it; jQuery will do that implicitly. What is it that you want to do with the data that you're fetching? — Pointy
– Pointy, Commented Feb 21, 2015 at 17:44
json is a dictionary structure , means key,value. if you want to read any value use. jsonobject.key — Pushker Yadav
– Pushker Yadav, Commented Feb 21, 2015 at 17:45
I want to be able to take each object e.g. 2009-01 and print its content — user2219097
– user2219097, Commented Feb 21, 2015 at 17:48

void · Accepted Answer · 2015-02-21 17:55:26Z

4

Use for...in loop.

The for..in statement iterates over the enumerable properties of an object, in arbitrary order.

   $.getJSON('data.json', function (data) {
        var resp = data;
        for(k in resp)
        {
          console.log(resp[k].bbcfour);
          console.log(resp[k].bbcnews24);
          console.log(resp[k].bbcone);
          // And so on
        }
    });

edited Feb 21, 2015 at 17:55

answered Feb 21, 2015 at 17:47

void

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3 Comments

user2219097 Over a year ago

thank you but i get an 'undefined object' as a result

charlietfl Over a year ago

should be more like console.log(data[k].bbcfour);

user2219097 Over a year ago

Thanks so much guys, appreciate the help as Im new to this. Thank you

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