dynamically change array property value in jquery

Question

My array contains NewColumn_1, NewColumn_2, NewColumn_3 etc... I am getting Max NewColumn_ Value in Array. Here NewColumn_SomeValue generating dynamically.

var products = [{
    "ProductID": 1,
    "ProductName": "Chai",
    NewColumn_1:'abc'
    NewColumn_2:'abc',
    NewColumn_3:'abc',
    NewColumn_4:'abc'
},{
    "ProductID": 2,
    "ProductName": "Chang",
    NewColumn_1:'def',
    NewColumn_2:'abc',
    NewColumn_3:'abc',
    NewColumn_4:'abc'
}]

var fieldValue = "NewColumn_" + (maxValueInArray);

products[i].NewColumn = jsonData[i].Title;

I need to products[i].fieldValue =jsonData[i].Title; i am unable to do. can any one help this.

there is no products[i].NewColumn, it should be column 1,2,3.... like products[i].NewColumn_1 — Bhushan Kawadkar
– Bhushan Kawadkar, Commented Sep 16, 2014 at 12:29
What does mean max in this context? Max value from all object fields (it will be quite strange to compare strings)? Or max index of NewColumn_X (which is always NewColumn_4)? — Regent
– Regent, Commented Sep 16, 2014 at 12:37
No. Here i am generating Newcloums. we can say NewColumn_4 is max one. it can be NewColumn_5, NewColumn_6,NewColumn_7 etc — Ram
– Ram, Commented Sep 16, 2014 at 12:56

Community · Accepted Answer · 2017-05-23 10:26:24Z

0

Try this code below

var lengths = [], length;

for (var i = 0; i < products.length; i++) {
    length = 0;
    for (var property in products[i]) {
        if (property.indexOf("NewColumn_") == 0) {
            length++;
        }
    }
    lengths.push(length);
}

var maximum = Math.max.apply(null, lengths);

Reference: How to get an object's properties in JavaScript / jQuery? and JavaScript: min & max Array values?

edited May 23, 2017 at 10:26

CommunityBot

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answered Sep 16, 2014 at 12:46

Mihir

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3 Comments

Ram Over a year ago

i am getting max value. just i need to give like products[i].fieldValue =jsonData[i].Title; i am unable to do that.

Mihir Over a year ago

products[i]['NewColumn_' + maximum] = data

Mihir Over a year ago

@Ram, please mark the answer as correct and close the post, thanks.

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